Students fret over the LSAT Logic Games section. Some students simply can’t crack this section. For others, the light bulb goes on, but they never finish the section in time. No matter what difficulty the LSAT Logic Games section presents to you, it is safe to say it involves a unique challenge many students have never experienced.
Nevertheless, this challenge can be overcome with a simple, straightforward approach. If you can master this approach and learn how to attack the common LSAT Logic Games questions this section will become the easiest section on the exam.
How is that possible? Logic Games are no different than puzzles. However, what makes them easier than puzzles is that a Logic Game gives you all the information you need to answer its corresponding questions. This fact yields two strategic advantages.
First, you don’t need to look elsewhere for critical pieces of the puzzle. Everything you need is right in front of you.
Second, because you have all the information you need, the game and the questions become predictable. Not only can you predict how certain scenarios will play out in a given game, you can use an answer to one question to predict an answer to another question. On an exam where time is of the essence, these advantages are monumentally critical.
To gain these advantages, however, you need to focus on processing and understanding the information that is on the page. That is the key to succeeding at Logic Games. You have to synthesize the information quickly and effectively.
The best method for processing the information in a given Logic Game and, then, answering the questions that follow is to diagram the Game’s scenarios and its rules so that you have a visual picture of what is and is not allowed. This picture will help you answer the questions more quickly by eliminating possibilities that do not fit your pre-determined diagram and helping you visually examine whether the remaining answers in each question “fit” the diagram on your page.
In this blog post, we will examine one sample (i.e., made-up) Logic Game. We will diagram the game and its rules. We will then answer each question, explain why each correct answer is right, and explain why each incorrect answer is wrong.
The more you become familiar with diagramming LSAT Logic Games, the more you will understand them on the exam, and the more quickly you will be able to analyze the problem and arrive at the correct answer.
Sample LSAT Logic Game
Let’s look at our sample LSAT Logic Game:
A car dealership employee must park seven cars. The cars are labeled A, B, C, D, E, F, and G. There are seven different consecutive parking spaces available for these cars. The parking spaces are numbered one through seven. Only one car can be parked in each space. The parking of the cars in the spaces is subject to the following rules:
- A and C must be parked in consecutive spaces.
- C must be parked in a higher-numbered space than E.
- A must be parked in a lower-numbered space than G.
- If E is not parked in the fourth space, then D must be parked in the fourth space.
- F and G cannot be parked in consecutively-numbered spaces.
1. Which of the following could be a possible list of the cars in the order that they are parked?
(A) ACDEFBG
(B) BFAECGD
(C) EACDFBG
(D) ECADGFB
(E) EFCADGB
2. If car A is parked in the third space, then which of the following must be true?
(A) E is parked in the fourth space.
(B) C is parked in the first space.
(C) B is parked in the sixth space.
(D) G is parked in the seventh space.
(E) F is parked in the fifth space.
3. Which of the following could be true?
(A) F is parked in the sixth space.
(B) C is parked in the fifth space.
(C) E is parked in the seventh space.
(D) A is parked in the first space.
(E) G is parked in the third space.
4. If B is parked in the third space, then each of the following could be true EXCEPT:
(A) A is parked in the fifth space.
(B) G is parked in the sixth space.
(C) D is parked in the fourth space.
(D) F is parked in the first space.
(E) C is parked in the sixth space.
5. If F is parked in the seventh space, then which of the following must be parked in the first space?
(A) B
(B) A
(C) D
(D) C
(E) E
As explained above, the best method for answering these questions is to diagram the rules above so that you have a visual picture of what is and is not allowed. Thus, before proceeding to or even looking at the questions, we will create a diagram that illustrates the seven spaces and which cars can be parked in each space. This diagram will help you answer the questions more quickly by eliminating possibilities that do not fit your pre-determined diagram and helping you visually examine whether the remaining answers in each question “fit” your diagram.
First, draw a diagram that looks like this:
Space | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
Car |
This diagram shows, as the problem above states, “seven different consecutive parking spaces” that are “numbered one through seven.” Now, we will write down and diagram the rules for the parking of the cars. We have five rules, so let’s examine each one individually:
Rule 1: A and C must be parked in consecutive spaces.
This rule is straightforward: A and C must be side-by-side in our diagram. Note that it does not say where in the diagram they must be. So simply list your first “rule” as follows underneath your diagram:
Space | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
Car |
Rule 1: AC
Note that the rule states “A and C must be parked in consecutive spaces.” That does not mean C must be parked after A, or that A must precede C. The rule is less strict than that. It states only that they must be parked in “consecutive” spaces. Thus, either can be parked before the other so long as they are parked consecutively. In other words, under Rule 1, the following order is possible:
Space | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
Car | A | C |
Rule 1: AC
So is this one:
Space | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
Car | C | A |
Rule 1: AC
In both scenarios, they are parked in “consecutive” parking spaces. So, after examining our first rule, your diagram should look like this:
Space | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
Car |
Rule 1: AC, CA
Let’s move on to the next rule:
Rule 2: C must be parked in a higher-numbered space than E.
This rule reveals much more about our parking possibilities because it helps us eliminate a parking space for both C and E. Let’s diagram it:
Space | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
Car |
Rule 1: AC, CA
Rule 2: E – C
Because C must be parked in a higher-numbered space than E, E could not possibly be parked in space 7 because there is no higher-numbered space where C could be parked. Thus, let’s make a note of that rule in space 7:
Space | 1 | 2 | 3 | 4 | 5 | 6 | 7(E) |
Car |
Rule 1: AC, CA
Rule 2: E – C
Also, because C must be parked in a higher-numbered space than E, C could not possibly be parked in space 1 because there is no lower-numbered space where E could be parked. Thus, let’s make a note of that rule in space 1:
Space | 1(C) | 2 | 3 | 4 | 5 | 6 | 7(E) |
Car |
Rule 1: AC, CA
Rule 2: E – C
By writing in C with a strikethrough in space 1 and E with a strikethrough in space 7, we will be reminded, as we proceed through the questions that C cannot be parked in the first space, and E cannot be parked in the last space.
In addition, notice that Rule 2 simply states that C must be parked in a “higher-numbered space” than E. It does not state that C and E must be parked in “consecutive” spaces like A and C. Nor does it state that C must be parked immediately after E. It merely states that C, wherever it is parked, must be parked in a higher-numbered space than E. Thus, without considering any other rules for now, E could be parked in space 2, and C could be parked in space 6 as shown:
Space | 1(C) | 2 | 3 | 4 | 5 | 6 | 7(E) |
Car | E | C |
Rule 1: AC, CA
Rule 2: E – C
Or E could be parked in space 3 and C in space 4:
Space | 1(C) | 2 | 3 | 4 | 5 | 6 | 7(E) |
Car | E | C |
Rule 1: AC, CA
Rule 2: E – C
As long as C is parked in a higher-numbered space than E, we have complied with Rule 2. Let’s move on to the next rule:
Rule 3: A must be parked in a lower-numbered space than G.
This rule is very similar to Rule 2, only it requires that one car (A) be parked in a lower-numbered, rather than higher-numbered, space. Also, like Rule 2, it helps us eliminate a space for the parking of two cars, which, in this case, are A and G. Before we proceed, however, let’s write in our third rule:
Space | 1(C) | 2 | 3 | 4 | 5 | 6 | 7(E) |
Car |
Rule 1: AC, CA
Rule 2: E – C
Rule 3: A – G
Now, because A must be parked in a lower-numbered space than G, A could not possibly be parked in space 7 because there is no higher-numbered space where G could be parked. Thus, let’s make a note of that rule in space 7:
Space | 1(C) | 2 | 3 | 4 | 5 | 6 | 7(E) (A) |
Car |
Rule 1: AC, CA
Rule 2: E – C
Rule 3: A – G
Also, because A must be parked in a lower-numbered space than G, G could not possibly be parked in space 1 because there is no lower-numbered space where A could be parked. Thus, let’s make a note of that rule in space 1:
Space | 1(C) (G) | 2 | 3 | 4 | 5 | 6 | 7(E) (A) |
Car |
Rule 1: AC, CA
Rule 2: E – C
Rule 3: A – G
By writing in G with a strikethrough in space 1 and A with a strikethrough in space 7, we will be reminded, as we proceed through the questions that G cannot be parked in the first space, and A cannot be parked in the last space.
In addition, notice that Rule 2 simply states that A must be parked in a lower-numbered space than G. It does not state that A and G must be parked in “consecutive” spaces like A and C. Nor does it state that A must be parked immediately before G. It merely states that A, wherever it is parked, must be parked in a lower-numbered space than G. Thus, without considering any other rules for now, A could be parked in space 2 and G in space 6 as shown:
Space | 1(C) (G) | 2 | 3 | 4 | 5 | 6 | 7(E) (A) |
Car | A | G |
Rule 1: AC, CA
Rule 2: E – C
Rule 3: A – G
Or A could be parked in space 3 and G in space 4:
Space | 1(C) (G) | 2 | 3 | 4 | 5 | 6 | 7(E) (A) |
Car | A | G |
Rule 1: AC, CA
Rule 2: E – C
Rule 3: A – G
As long as A is parked in a lower-numbered space than G, we have complied with Rule 3. On to the next rule . . .
Rule 4: If E is not parked in the fourth space, then D must be parked in the fourth space.
Like Rules 2 and 3, this rule helps us narrow down which cars can be parked in which spaces. In this case, this rule only allows E or D to be parked in space 4. Let’s write in our rule first (this is optional, since we’ll make a note of this in the actual diagram, as shown in the next step):
Space | 1(C) (G) | 2 | 3 | 4 | 5 | 6 | 7(E) (A) |
Car |
Rule 1: AC, CA
Rule 2: E – C
Rule 3: A – G
Rule 4: E or D in space 4
Then let’s make a note in the actual diagram that only E or D can be parked in space 4:
Space | 1(C) (G) | 2 | 3 | 4(E or D) | 5 | 6 | 7(E) (A) |
Car |
Rule 1: AC, CA
Rule 2: E – C
Rule 3: A – G
Rule 4: E or D in space 4
Let’s proceed to the last rule:
Rule 5: G and F cannot be parked in consecutively numbered spaces.
This rule is the opposite of Rule 1. Whereas Rule 1 requires that two cars (A and C) be parked in consecutive spaces, this rule prohibits two cars (G and F) from being parked in consecutive spaces. It makes no difference that the phrase “consecutively numbered” is used here, but the term “consecutive” is used in Rule 1. They effectively mean the same thing. Also, notice that the rule does not specify any sequence, such as a rule that G cannot be parked immediately before F. Rather, it prohibits all scenarios in which G and F are “parked in consecutively numbered spaces.” Thus, let’s write in our final rule:
Space | 1(C) (G) | 2 | 3 | 4(E or D) | 5 | 6 | 7(E) (A) |
Car |
Rule 1: AC, CA
Rule 2: E – C
Rule 3: A – G
Rule 4: E or D in space 4
Rule 5: GF, FG
Notice also that the rule does not state anything regarding which car (G or F) can be parked before the other. That doesn’t matter. It merely states that they cannot be parked consecutively. Thus, G can be parked before F but not immediately before F:
Space | 1(C) (G) | 2 | 3 | 4(E or D) | 5 | 6 | 7(E) (A) |
Car | G | F |
Rule 1: AC, CA
Rule 2: E – C
Rule 3: A – G
Rule 4: E or D in space 4
Rule 5: GF, FG
And vice versa: F can be parked before G but not immediately before G. Either can be parked before the other so long as they are not parked consecutively.
Space | 1(C) (G) | 2 | 3 | 4(E or D) | 5 | 6 | 7(E) (A) |
Car | F | G |
Rule 1: AC, CA
Rule 2: E – C
Rule 3: A – G
Rule 4: E or D in space 4
Rule 5: GF, FG
Now that we’ve diagrammed our rules and created a working chart of the parking order with a minimum set of guidelines as to which cars can be parked in which spaces, the most important thing you can do before proceeding to the questions is to infer additional rules based on the ones set forth above. Any additional rules you can infer will create shortcuts you can exploit when you answer the questions. These shortcuts will save you valuable time.
In this particular game, one way to create additional rules is to look at your diagram and rules and determine which rules allow you to create sequences. In other words, which rules can you combine to form a sequence of three or more cars?
Space | 1(C) (G) | 2 | 3 | 4(E or D) | 5 | 6 | 7(E) (A) |
Car |
Rule 1: AC, CA
Rule 2: E – C
Rule 3: A – G
Rule 4: E or D in space 4.
Rule 5: GF, FG
Glancing at your rules, you should notice the following:
Rules 1 and 2 (a) both affect C, (b) affect three different cars, and (c) can be combined to form a longer sequence.
Rules 1 and 3 (b) both affect A, (b) affect three different cars, and (c) can be combined to form a longer sequence.
These Rules allow you to create sequences of cars that you can use as shortcuts when determining which parking arrangements are possible or not possible.
For example, Rule 1 requires that A and C be parked consecutively. Rule 2 requires that C be parked in a higher-numbered space than E. Thus, we know that, wherever C and A are parked, E must be parked before them. In addition, wherever E is parked, we know that C and A must be parked after E. So, this sequence would look like this:
E – AC/CA
E must be parked in a lower-numbered space (or before) the consecutive parking of A and C. This sequence allows us to map out, with relatively good precision, the parking order of three cars. Whenever a question or answer places E, A, or C in one of the seven spaces, we can use the sequence above to predict (to some extent) where the other two cars might be parked.
We can do the same thing with Rules 1 and 3 and add to this sequence. Rule 1 requires that A and C be parked consecutively. Rule 3 requires that A be parked in a lower-numbered space than G. Thus, we know that, wherever C and A are parked (which, again, must be consecutively), G must be parked after them. In addition, wherever G is parked, we know that C and A must be parked before G. So, this sequence would look like this:
AC/CA – G
A and C (again, parked consecutively) must be parked in lower-numbered spaces than G. This sequence also allows us to map out, with relatively good precision, the parking order of three cars. Whenever a question or answer or answer places either A, C, or G in one of the seven spaces, we can use the sequence above to predict (to some extent) where the other two cars might be parked.
Furthermore, if we combine the sequences, we will have a larger sequence that affects four cars:
E – AC/CA – G
In other words, E must be parked in a lower-numbered space than (i.e., before) the consecutive parking of A and C, which must be parked in lowered-numbered spaces than (i.e., before) G. This larger sequence also allows us to map out, with relatively good precision, the parking of four cars. Whenever a question or answer or answer places E, A, C, or G in one of the seven spaces, we can use the sequence above to predict (again, to some extent) where the other three cars will be parked.
So, because we have effectively combined Rules 1, 2, and 3 into a sequence, let’s replace Rules 1, 2, and 3 underneath our diagram with this sequence:
Space | 1(C) (G) | 2 | 3 | 4(E or D) | 5 | 6 | 7(E) (A) |
Car |
Sequence: E – AC/CA – G
Rule 4: E or D in space 4.
Rule 5: GF, FG
Why eliminate three rules, replace it with this sequence, and make it special? Because it affects four cars. Remember: time is critical on this exam. When you are dealing with a question and looking to eliminate answers, considering how a sequence that implicates four cars affects your given question and answers will help you eliminate answers quicker than dealing with a rule that only implicates two cars. Furthermore, when – through inference – you can simplify your rules, do so! One combined sequence is better to interpret and apply than three individual rules.
A few more things before we proceed to the questions.
First, our new Sequence helps us write in some additional rules on our diagram. The Sequence requires that E be parked in a lower-numbered space than A, C, and G. None of the latter three cars can ever be parked before E. We have already noted in our chart that neither G nor C can ever be parked in space 1:
Space | 1(C) (G) | 2 | 3 | 4(E or D) | 5 | 6 | 7(E) (A) |
Car |
Now, we can also note that A can never be parked in space 1:
Space | 1(C) (G) (A) | 2 | 3 | 4(E or D) | 5 | 6 | 7(E) (A) |
Car |
Why? Because, according to our Sequence, none of these three cars – G, C, or A – can ever be parked in lower-numbered spaces than E. Thus, placing any of them in space 1 would violate that rule because there is no lower-numbered space in which E can be parked.
The Sequence also requires that G must be parked in a higher-numbered space than E, A, and C. Thus, none of the latter three cars can ever be parked in higher-numbered spaces than G. We have already noted in our diagram that neither A nor E can ever be parked in space 7:
Space | 1(C) (G) (A) | 2 | 3 | 4(E or D) | 5 | 6 | 7(E) (A) |
Car |
Now, we can also note that C can never be parked in space 7:
Space | 1(C) (G) (A) | 2 | 3 | 4(E or D) | 5 | 6 | 7(E) (A) (C) |
Car |
Why? For the same reasons as our previous example. According to our Sequence, none of these three cars – E, C, or A – can ever be parked in higher-numbered spaces than G. Thus, placing any of them in space 7 would violate that rule because there is no higher-numbered space in which G can be parked.
These are not the only additional notations we can infer and write into on our diagram. Let’s look again at our Sequence:
E – AC/CA – G
If E must be parked in a lower-numbered space than A, C, and G, that means it must be parked in a higher-numbered space than three cars. This means parking E in a space that precedes fewer than three cars would violate our Sequence. For instance, parking E in space 5 would violate our Sequence because only two spaces follow space 5, and there are three cars that must be parked after E:
Space | 1(C) (G) (A) | 2 | 3 | 4(E or D) | 5 | 6 | 7(E) (A) (C) |
Car | E |
So, based on this information, we should pencil in the spaces in which E cannot be parked. To do this, cross out the spaces that do not precede three or more spaces. Looking at our chart, we should prohibit E from being parked in spaces 5, 6, and 7 (which we’ve already noted):
Space | 1(C) (G) (A) | 2 | 3 | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car |
Parking E in any of these spaces would violate our Sequence because there would not be a sufficient number of spaces (we need three of them) in which to park the three cars (A, C, and G) that, according to our Sequence, must follow E in some fashion.
Just as we did for E, we can do the same for G. Let’s look again at our Sequence:
E – AC/CA – G
If G must be parked in a higher-numbered space than E, A, and C, that means it must be parked in a higher-numbered space than three cars. This means parking G in a space that follows fewer than three spaces would violate our Sequence. For instance, parking G in space 3 would violate our Sequence because only two spaces precede space 3, and there are three cars that must be parked in lower-numbered spaces than G:
Space | 1(C) (G) (A) | 2 | 3 | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | G |
So, based on this information, we should write in the spaces in which G cannot be parked. To do this, cross out the spaces that do not follow three or more spaces. Looking at our chart, we should prohibit G from being parked in spaces 1 (which we’ve already noted), 2, and 3:
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car |
Parking G in any of these spaces would violate our Sequence because there would not be a sufficient number of spaces (we need three of them) in which to park the three cars (E, C, and A) that, according to our Sequence, must precede G in some fashion.
(You probably noticed that G also cannot be parked in space 4 because, according to Rule 4, only E or D can be parked there. But, since this is true for every other car that is not E or D, let’s not cross out space 4 for G like we did for spaces 1, 2, and 3, because that means we would have to do it for every other car that is not E or D. We don’t have enough space for that, and Rule 4 is sufficient.)
Second, with all of the above information, you can now narrow down the parking possibilities into TWO scenarios: the scenario where E is in space 4 and the scenario where E is not in space 4.
For the first scenario, if E is in space 4 . . .
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E |
. . . we can use our Sequence (E – AC/CA – G) to map out a good portion of the parking order. We know that A, C, and G must fill out spaces 5, 6, and 7 in some order. Neither A nor C can be parked in space 7. So that leaves G for space 7:
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | G |
Then, A and C can be parked in spaces 5 or 6 in whatever order:
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | G |
It doesn’t matter what order A and C are in so long as they are parked consecutively. That leaves B, D, and F. We don’t have any rules that help us predict where those cars would be parked. The only Rules are 4 and 5. Rule 4 requires that E or D be parked in space 4. Since E is parked there in this scenario, we have satisfied Rule 4. Rule 5 requires that F and G not be parked consecutively. Since G is parked in space 7 and will be preceded by either A or C, we have satisfied Rule 5. Nothing else helps us predict where B, D, or F might go. Since there are several possibilities, we will leave our first scenario as is:
Scenario 1
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | G |
For the second scenario, if D (instead of E) is in space 4 . . .
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | D |
. . . we can again use our Sequence (E – AC/CA – G) to map out a good portion of the parking order. There are several variables with E. E could be parked in space 1, 2, or 3, so long as A/C/G are parked in higher-numbered spaces. So E yields too many possibilities for our purposes right now. However, we know that A and C must be parked consecutively. Because D splits up the ordering, there are only two possibilities for consecutive spaces for the A/C combination (spaces 2 and 3 or spaces 5 and 6), since neither A nor C can be parked in either spaces 1 or 7. Thus, we have two possible scenarios (which we will label Scenario 2 and Scenario 3). Either A and C are parked in spaces 2 and 3:
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | A/C | C/A | D |
Or A and C are parked in spaces 5 and 6:
Scenario 3
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | D | A/C | C/A |
In Scenario 2, the only option for E is space 1:
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | D |
B would then have to be parked in spot 6 since F and G cannot be parked consecutively:
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | D | B |
Then F and G can be parked in spots 5 and 7 in whatever order:
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | D | F/G | B | G/F |
That is as far as we can go with Scenario 2, but, as you can see, it does A LOT for us. As for Scenario 3, the only option for G is space 7:
Scenario 3
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | D | A/C | C/A | G |
That leaves B, E, and F for spaces 1, 2, and 3. No other rules help us predict where to park those remaining cars, so we will leave Scenario 3 as is.
So we have three possible scenarios to work with when we answer the five questions that follow:
Scenario 1
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | G |
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | D | F/G | B | G/F |
Scenario 3
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | D | A/C | C/A | G |
Finally! Let’s proceed to the questions!
Questions
Question 1
1. Which of the following could be a possible list of the cars in the order that they are parked during the day?
(A) ACDEFBG
(B) BFAECGD
(C) EACDFBG
(D) ECADGFB
(E) EFCADGB
This question asks which of five parking scenarios is possible. Thus, four of the five listed in (A) through (E) are not possible. This is a common question and usually follows the Logic Game as the first question. It merely requires that you plug in the different rules, eliminate the answer choices that violate the rules, and then, by process of elimination, arrive at the correct answer.
If you recall, we have our three scenarios:
Scenario 1
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | G |
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | D | F/G | B | G/F |
Scenario 3
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | D | A/C | C/A | G |
Let’s look at the first answer choice:
(A) ACDEFBG
Does it violate any rules? Yes! A is in space 1. Our notations above prohibit A from being in space 1. Thus, answer choice A is incorrect, and we can safely eliminate it:
(A) ACPSTNG
(B) BFAECGD
(C) EACDFBG
(D) ECADGFB
(E) EFCADGB
Let’s look at the next answer choice:
(B) BFAECGD
Does it violate any rules? Yes! E is in space 4, so this scenario relates to our Scenario 1:
Scenario 1
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | G |
In Scenario 1, some combination of A and C must be parked in spaces 5 and 6, and G must be parked in space 7. However, in our answer choice, G and D are in spaces 6 and 7:
(B) BFAECGD
That arrangement violates our notations above and the Sequence we inferred from the first three rules: E – AC/CA – G. That Sequence requires that E be parked in a lower-numbered space than A and C. However, in our answer choice, A is parked in a lower-numbered space than E:
(B) BFAECGD
Thus, answer choice B is incorrect, and we can safely eliminate it.
(B) BFAECGD
(C) EACDFBG
(D) ECADGFB
(E) EFCADGB
Let’s look at answer choice C:
(C) EACDFBG
Does it violate any rules? It doesn’t look like it! Let’s walk through it. Because D is parked in space 4, and F is in space 5, this arrangement implicates our second Scenario:
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | D | F/G | B | G/F |
The arrangement in answer choice C complies with this Scenario. E is parked in space 1. A and C are in spaces 2 and 3. As mentioned above, D and F are in spaces 4 and 5. B is in space 6. Finally, G is in space 7. Our Sequence isn’t violated because E is parked in a lower-numbered space than A and C, which are parked in lower-numbered spaces than G. Nor are Rules 4 or 5 violated because D is in space 4, and F and G are not parked consecutively. Thus, answer choice C is the correct answer!
(C) EACDFBG
(D) ECADGFB
(E) EFCADGB
At this point, you could move on to Question 2 and save time. You don’t have to examine each of the remaining two answers. Remember that this is a timed exam, and whenever you have a correct answer and are 100% sure that it is correct (as you are here), save time and move on!
For our purposes here, though, let’s look at what is wrong with answer choices D and E. Answer choice D shows us F and G parked consecutively:
(D) ECADGFB
Thus, it is not correct because that violates Rule 5.
(C) EACDFBG
(D) ECADGFB
(E) EFCADGB
As for answer choice E, neither E nor D are in space 4; A is:
(C) EACDFBG
(E) EFCADGB
Thus, answer choice E is incorrect because it violates Rule 4.
(C) EACDFBG
(E) EFCADGB
So answer choice C as our correct answer for Question 1:
1. Which of the following could be a possible list of the cars in the order that they are parked during the day?
(A) ACDEFBG
(B) BFAECGD
(C) EACDFBG
(D) ECADGFB
(E) EFCADGB
Now on to Question 2 . . .
Question 2
2. If car A is parked in the third space, then which of the following must be true?
(A) E is parked in the fourth space.
(B) C is parked in the first space.
(C) B is parked in the sixth space.
(D) G is parked in the seventh space.
(E) F is parked in the fifth space.
Unlike Question 1, which asked us which of five parking scenarios was possible, Question 2 introduces an additional rule or condition (“A is parked in the third space”) and asks which of five parking possibilities is correct in light of that new rule. To answer this question, we add this additional rule to the mix and then, before considering any of the answers, map out the rest of the parking order in our diagram.
First, let’s write in our additional rule:
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | A |
Sequence 1: E – AC/CA – G
Rule 4: E or D in space 4.
Rule 5: GF, FG
Next, let’s map out the rest of the parking order. This will help us narrow down our possibilities and, thus, eliminate answer choices.
In mapping out the rest of the parking order, you could go through the Sequence and then Rules 4 and 5 and then fill in the rest of the order. However, we can save you a few seconds and perhaps a few minutes. Remember our Scenarios?
Scenario 1
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | G |
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | D | F/G | B | G/F |
Scenario 3
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | D | A/C | C/A | G |
Which Scenario above could have A in space 3? Scenario 2! Neither Scenarios 1 or 3 could have A in space 3. Thus, Scenario 2 maps out the rest of the order for us:
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | C | A | D | F/G | B | G/F |
The only variables left are F and G, which can be parked in spaces 5 or 7. We don’t have enough information to be able to determine where they go exactly, but that doesn’t matter. We have just saved a ton of time by having Scenario 2 in our back pocket! Let’s look at the answer choices:
2. If car A is parked in the third space, then which of the following must be true?
(A) E is parked in the fourth space.
(B) C is parked in the first space.
(C) B is parked in the sixth space.
(D) G is parked in the seventh space.
(E) F is parked in the fifth space.
Notice the question asks “which of the following must be true?” Thus, we must find the answer choice that is true under every circumstance. We are not looking for something that could be true. The question asks what must be true. Let’s begin with answer choice A:
(A) E is parked in the fourth space.
That is false because D is in space 4. Thus, answer choice A is incorrect:
(A) E is parked in the fourth space.
(B) C is parked in the first space.
(C) B is parked in the sixth space.
(D) G is parked in the seventh space.
(E) F is parked in the fifth space.
Let’s move to answer choice B:
(B) C is parked in the first space.
That is false as well because E is in space 1. So answer choice B is incorrect:
(B) C is parked in the first space.
(C) B is parked in the sixth space.
(D) G is parked in the seventh space.
(E) F is parked in the fifth space.
Answer choice C:
(C) B is parked in the sixth space.
B is indeed in space 6 and must be for this order to work. So answer choice C is the correct answer!
(C) B is parked in the sixth space.
(D) G is parked in the seventh space.
(E) F is parked in the fifth space.
Again, we could move on here to Question 3 because we are sure answer choice C is the correct answer. But, for our purposes here, let’s examine the remaining two answers. First, answer choice D:
(D) G is parked in the seventh space.
G could be parked in space 7. But it doesn’t have to be:
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | C | A | D | F/G | B | G/F |
There is a version of Scenario 2 where G is parked in space 5:
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | C | A | D | G | B | F |
Thus, because G doesn’t have to be in space 7, answer choice D is incorrect:
(C) B is parked in the sixth space.
(D) G is parked in the seventh space.
(E) F is parked in the fifth space.
Let’s look at answer choice E:
(E) F is parked in the fifth space.
Like with answer choice D, F could be parked in space 5. But it doesn’t have to be:
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | C | A | D | F/G | B | G/F |
There is a version of Scenario 2 where F is parked in space 7:
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | C | A | D | G | B | F |
Thus, because F doesn’t have to be in space 5, answer choice E is incorrect:
(C) B is parked in the sixth space.
(E) F is parked in the fifth space.
That leaves answer choice C as our correct answer:
2. If car A is parked in the third space, then which of the following must be true?
(A) E is parked in the fourth space.
(B) C is parked in the first space.
(C) B is parked in the sixth space.
(D) G is parked in the seventh space.
(E) F is parked in the fifth space.
On to Question 3 . . .
Question 3
3. Which of the following could be true?
(A) F is parked in the sixth space.
(B) C is parked in the fifth space.
(C) E is parked in the seventh space.
(D) A is parked in the first space.
(E) G is parked in the third space.
Notice right away that we are out of the “must be true” world and into the merely probable “could be true” world. A difference, for sure, but not more difficult. Because Question 3 does not provide us with any additional rules or conditions, the fastest approach here will be to plug each of these answer choices into our three Scenarios and apply our Sequence and Rules, and see what works (like we did, in part, with Question 1). If an answer doesn’t work at all, it is incorrect. If it could work in any of the Scenarios, it’s the correct answer.
To recap, here are our three Scenarios:
Scenario 1
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | G |
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | D | F/G | B | G/F |
Scenario 3
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | D | A/C | C/A | G |
Let’s start with answer choice A:
(A) F is parked in the sixth space.
Could F be parked in space 6? No! That could never happen. In Scenarios 1 and 3, either A or C must be parked in space 6. In Scenario 2, B must go in space 6. So answer choice A is incorrect:
(A) F is parked in the sixth space.
(B) C is parked in the fifth space.
(C) E is parked in the seventh space.
(D) A is parked in the first space.
(E) G is parked in the third space.
What about answer choice B?
(B) C is parked in the fifth space.
C could be parked in space 5 in either Scenario 1 or Scenario 3. So answer choice B is our correct answer!
(B) C is parked in the fifth space.
(C) E is parked in the seventh space.
(D) A is parked in the first space.
(E) G is parked in the third space.
For the sake of this analysis, let’s examine the remaining three answer choices, beginning with answer choice C:
(C) E is parked in the seventh space.
That violates our Sequence and our notations, so answer choice C is incorrect:
(B) C is parked in the fifth space.
(C) E is parked in the seventh space.
(D) A is parked in the first space.
(E) G is parked in the third space.
What about answer choice D?
(D) A is parked in the first space.
That doesn’t work either because it violates our Sequence and notations. Answer choice D is incorrect:
(B) C is parked in the fifth space.
(D) A is parked in the first space.
(E) G is parked in the third space.
Answer choice E?
(E) G is parked in the third space.
That violates our Sequence and our notations as well, so answer choice E is incorrect:
(B) C is parked in the fifth space.
(E) G is parked in the third space.
That leaves answer choice B as our correct answer:
3. Which of the following could be true?
(A) F is parked in the sixth space.
(B) C is parked in the fifth space.
(C) E is parked in the seventh space.
(D) A is parked in the first space.
(E) G is parked in the third space.
On to Question 4!
Question 4
4. If B is parked in the third space, then each of the following could be true EXCEPT:
(A) A is parked in the fifth space.
(B) G is parked in the sixth space.
(C) D is parked in the fourth space.
(D) F is parked in the first space.
(E) C is parked in the sixth space.
Like Question 2, Question 4 introduces an additional rule or condition. It then asks which of five parking orders is false. Because it posits that “each of the following [five answers] could be true,” by prefacing the answers with “EXCEPT,” it effectively asks which of those five answers cannot be true.
So, as we did with Question 2, let’s add our new rule (B parked in the third space):
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | B |
Sequence 1: E – AC/CA – G
Rule 4: E or D in space 4.
Rule 5: GF, FG
Like we did with Question 2, we need to map out the rest of the parking order if we can. To do that, let’s look at our Scenarios:
Scenario 1
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | G |
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | D | F/G | B | G/F |
Scenario 3
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | D | A/C | C/A | G |
Which Scenario above could have B in space 3? Scenarios 1 and 3! Those Scenarios map out the rest of the possible parking orders for us:
Scenario 1
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | B | E | A/C | C/A | G |
Scenario 3
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | B | D | A/C | C/A | G |
The remaining cars (D and F in Scenario 1, and E and F in Scenario 3) could go in spaces 1 and 2 in whatever order, as follows:
Scenario 1
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | D/F | F/D | B | E | A/C | C/A | G |
Scenario 3
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E/F | F/E | B | D | A/C | C/A | G |
Let’s now go back to the question:
4. If B is parked in the third space, then each of the following could be true EXCEPT:
(A) A is parked in the fifth space.
(B) G is parked in the sixth space.
(C) D is parked in the fourth space.
(D) F is parked in the first space.
(E) C is parked in the sixth space.
Let’s start with answer choice A:
(A) A is parked in the fifth space.
A could be parked in space 5 in both Scenarios. So answer choice A is incorrect:
(A) A is parked in the fifth space.
(B) G is parked in the sixth space.
(C) D is parked in the fourth space.
(D) F is parked in the first space.
(E) C is parked in the sixth space.
What about answer choice B?
(B) G is parked in the sixth space.
G cannot be parked in space 6 under any circumstances. In both Scenarios, it must be parked in space 7. Thus, answer choice B is our correct answer!
(B) G is parked in the sixth space.
(C) D is parked in the fourth space.
(D) F is parked in the first space.
(E) C is parked in the sixth space.
Let’s examine the remaining answer choices, beginning with answer choice C:
(C) D is parked in the fourth space.
D could be parked in space 4 in Scenario 3. So, answer choice C is incorrect:
(B) G is parked in the sixth space.
(C) D is parked in the fourth space.
(D) F is parked in the first space.
(E) C is parked in the sixth space.
Let’s look at answer choice D:
(D) F is parked in the first space.
F could be parked in space 1 in both Scenarios. So answer choice D is incorrect:
(B) G is parked in the sixth space.
(D) F is parked in the first space.
(E) C is parked in the sixth space.
Now, answer choice E:
(E) C is parked in the sixth space.
C could be parked in space 6 in both Scenarios. So answer choice E is incorrect:
(B) G is parked in the sixth space.
(E) C is parked in the sixth space.
That leaves answer choice B as our correct answer:
4. If B is parked in the third space, then each of the following could be true EXCEPT:
(A) A is parked in the fifth space.
(B) G is parked in the sixth space.
(C) D is parked in the fourth space.
(D) F is parked in the first space.
(E) C is parked in the sixth space.
Finally, on to Question 5 . . .
Question 5
5. If F is parked in the seventh space, then which of the following must be parked in the first space?
(A) B
(B) A
(C) D
(D) C
(E) E
Like Questions 2 and 4, this one introduces an additional rule for us (F parked in space 7). Let’s cut to the chase: Which of our Scenarios could feature F in space 7?
You guessed it! Scenario 2!
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | D | F/G | B | G/F |
Let’s reconfigure Scenario 2 so that F is in space 7:
Scenario 2
Space | 1(C) (G) (A) | 2(G) | 3(G) | 4(E or D) | 5(E) | 6(E) | 7(E) (A) (C) |
Car | E | A/C | C/A | D | G | B | F |
We can’t do anything with A and C, so we will leave them as is. Let’s move on to the answer choices:
5. If F is parked in the seventh space, then which of the following must be parked in the fifth space?
(A) B
(B) A
(C) D
(D) C
(E) E
The question is simple: Which car must be in space 1? If you look at our Scenario above, E must be in space 1. No other car can be parked in space 1. Accordingly, the correct answer choice is answer choice E:
5. If F is parked in the seventh space, then which of the following must be parked in the first space?
(A) B
(B) A
(C) D
(D) C
(E) E
The method above represents the best way for you to approach LSAT Logic Games. You must diagram the Game so that you can process and understand the information it provides. When doing so, infer as much as possible from the information given. Then, use your diagram to answer the questions. Remember: It’s no different than a puzzle, and all the information you need is right in front of you.